Question

O is the centre of a circle of radius 8 cm. The tangent
at a point A on the circle cuts a line through O at
B such that AB = 15 cm. Find OB .​

Answer 1

Answer:by using Pythagoras theorem and by getting oab as 90°

Step-by-step explanation:

Answer 2

OB=17 cm

Step-by-step explanation:

O is the center of circle

Radius of circle=8 cm

AB=15 cm

In triangle OAB

$OA^2+AB^2=OB^2$

Using Pythagoras theorem:

$(Hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2$

Substitute the values then we get

$OB^2=(8)^2+(15)^2$

$OB^2=64+225$

$OB^2=289$

$OB=\sqrt{289}=17 cm$

Hence, OB=17 cm

#Learns more:

https://brainly.in/question/13103953