O is the centre of a circle. OM perpendicular chord AB.
If chord AB is 16 cm, Find AM.
Answers
Answered by
0
Step-by-step explanation:
OA is the radius of the circle
Perpendicular drawn from centre to a chord bisects the chord.
Therefore AM=
2
1
AB
AM=10cm
Thus, triangle OMA is right angled triangled at ∠OMA.
∠OMA=90
∘
.
By Pythagoras theorem,
OA
2
=OM
2
+MA
2
OA=
OM
2
+MA
2
OA=
(2
11
)
2
+10
2
OA=
144
cm
OA=12cm
Radius of a circle is 12cm.
Answered by
0
Step-by-step explanation:
OA is the radius of the circle
Perpendicular drawn from centre to a chord bisects the chord.
Therefore AM=
2
1
AB
AM=10cm
Thus, triangle OMA is right angled triangled at ∠OMA.
∠OMA=90
∘
.
By Pythagoras theorem,
OA
2
=OM
2
+MA
2
OA=
OM
2
+MA
2
OA=
(2
11
)
2
+10
2
OA=
144
cm
OA=12cm
Radius of a circle is 12cm.
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