O is the centre of circle.AB is tangent to the circle at the point p.If angle APQ=58,then measure angle PQB is
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We know that, <APO = 90° (As AB is the tangent)
Thus <QPO = 90° - 58° = 32°
Now, in triangle OPQ, OP = OQ (radii of the circle)
Therefore <QPO = <OQP = 32°
Thus <PQB = <OQP = 32°
Hope that helps !!
Thus <QPO = 90° - 58° = 32°
Now, in triangle OPQ, OP = OQ (radii of the circle)
Therefore <QPO = <OQP = 32°
Thus <PQB = <OQP = 32°
Hope that helps !!
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