Question

O is the centre of circle. find its radius using Pythagoras theorem​

Answer 1

Answer:

✬Formula used:

$ʜʏᴘᴏ = \sqrt{(ʙᴀsᴇ)^{2}+(ʜᴇɪɢʜᴛ) ^{2} }$

✬Solution:

Given,

Base=10cm

Height=24cm

$⟶ʜʏᴘᴏ = \sqrt{(10)^{2} + (24)^{2} }$

$⟶ʜʏᴘᴏ = \sqrt{100 + 576}$

$⟶ʜʏᴘᴏ = \sqrt{676}$

$⟶ʜʏᴘᴏ = 26cm$

Thus, The diameter of the circle is 26cm.

Now,

Radius=Diameter/2

⟶Radius=26/2

⟶Radius=13cm

Therefore, The radius of the circle is 13cm.

Answer 2

O= centre of circle

?= radius

using- Pythagoras theorem

triangle=

24cm - AB

10cm - BC

O- CA

O²=24²+10²

O²=576+100

O²=676

O=26²

26/2=13

Radius = 13cm