Question

O is the centre of circle of radius 15cm M is a point at a distance of 5cm from O AMB is any chord of the circle passing through M then the value of. AM*MB
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Answer 1

Answer:

Radius of a circle is 5 cm.

Therefore OB = 5 cm.

Perpendicular drawn to the chord from the centre bisects the chord.

Therefore AM = MB

Triangle OMB is right angled triangle at M

∠OMB=90∘

By Pythagoras theorem;

OB2=OM2+MB2

MB=OB2−OM2

 MB=52−42

MB=3cm

Step-by-step explanation:

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Answer 2

Answer:

ANSWER IS IN THE PICTURE

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