Question

O is the centre of circle with radius 5cm chords AB and CD are parallel a b is equal to 6 cm and CD is equal to 8 centimetre if PQ is distance between AB and CD than PQ is equal to

Answer 1

Answer:

Step-by-step explanation:

Given,

Applying Pythagoras theorem in ∠AOP and △COQ

In △AOP,AO2=AP2+PO2

=> AO2=(AB2)2+PO2

=> (5)2=(4)2+x2

=> 25−16=x2

∴x=9–√= 3 cm

In △COQ,

CO2=OQ2+CQ2

=> CO2=OQ2+(CD2)2

=> 25−9=y2

=> y=16−−√=4cm

Therefore, PQ = PO+OQ = 3+4 = 7 cm