Question

o is the centre of the circle and ab is the diameter if oda = 90 and OB = BC find angle 1​

Answer 1

Given:  oda = 90 and o is the center of the circle.

            OB = BC

To Find = Angle 1

Solution: OB=OP (since both are the radius of the same circle )

                 OB=√(3^2+1^2)=√10

                 hence OP=√10

                 Therefore the point P is (√10,0).