O is the centre of the circle and ABC and EDC are tangents to the circle. Find the angle of BCD. I've only got three marks with this answer please help! BFD = BD x 2 76 = BD x 2 BD = 152 BOD = BD = 152 BOD + CDO + BCD + CBO = 360˚ 152 + 90 + BCD + 90 = 360˚ BCD = 360 - 180 - 152˚ Because angle at centre is twice the angle at the circumference thus angle BCD = 28˚
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