Question

O is the centre of the circle and length of the chord is 8 cm , op is perpendicular to cord ab if line op is 3 cm then find radius of the circle .
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Answer 1

Answer:

radius of the circle is 5 cm

hope it helps you buddy

Step-by-step explanation:

as per the theorem perpendicular from the centre divides the chord into two equal parts

and by applying Pythagoras theorem

we get R=√(3^2+4^2)

R=√(9+16)

R=√(25)

R=5 cm

Answer 2

Given O is the center of circle ,OM=3 cm and AB=8 cm

Join O to A and B

In figure OM show that the perpendicular from center O on cord AB

WE know that Perpendicular from the Center of a Circle to a Chord Bisects the Chord.

Then AM = BM

So AM = BM

= AB / 2

= 8 / 2

= 4 cm

Δ AOM

(AO)² =(AM)² +(OM)² = (4)² + (3)²

=16 + 9=25

⇒AO = 5cm