Question

O is the centre of the circle, and length of the chord is 8cm seg OP chord AB If l (OP) =3cm then find the radius of the circle.​

Answer 1

Answer:

Given o is the center of circle ,OM=3 cm and AB=8 cm

Join O to A and B

In figure OM show that the perpendicular from center O on cord AB

WE know that Perpendicular from the Center of a Circle to a Chord Bisects the Chord.

Then AM=BM

So AM=BM=

2

AB

=

2

8

=4cm

ΔAOM

(AO)

2

=(AM)

2

+(OM)

2

=(4)

2

+(3)

2

=16+9=25

⇒AO=5cm

Then AO is the radius of circle is 5 cm

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