Question

o is the centre of the circle and pqr is an isosceles triangle with pq =qr . find angle pqr​

Answer 1

In  △PQR, we have

PQ = PR

⇒  ∠PQR = ∠PRQ

⇒ ∠PRQ = 35˚

∴   ∠QPR = 180˚ - (∠PQR + ∠PRQ)

= 180˚ - (35˚ + 35˚) = 110˚.

Since, PQTR  is a cyclic quadrilateral.

∴  ∠P + ∠T = 180˚

⇒ ∠T = 180˚ – 110˚ = 70˚

In cyclic quadrilateral QSRT, we have

∠S + ∠T = 180˚

⇒  ∠S = 180˚ - 70˚ = 110