Question

o is the centre of the circle angle aob= bo ; find angle A and angle B

Answer 1

(1)∠ACB=

2

1

∠AOBbisectors

=

2

1

× (

360

0

−

140

0

) =

2

1

×220=110

0

(2)∠OBC=360

0

−(∠AOB+∠OAC+∠ACB)

=360

0

− (

140

0

+

50

o

+

110

0

)

=360

0

−300

0

=60

0

(3)since,OA&OBisradius

∴ΔOABisisoscelesΔ

∴∠OAB=

2

1

(

180

0

−

140

0

) =

2

1

×40

0

=20

0

(4)∠CBA−∠OBC−∠OBA

=∠OBC−∠OAB[ΔOABisisoscelesΔ]

=60

0

−20

0

−40

0

thank u for asking