Question

O is the centre of the circle.Aob 60 then find acb and ADB

Answer 1

→ Given Question:-

→ O is the centre of the circle.AOB 60 then find ACB  and ADB?

→ To find:-

→ Find ACB and ADB?

→ Solution:-

→ ∠AOB + ∠AOC = 180°

→ [ ∵ Sum of angle is a straight line ]

→ ∠AOC = 180° - 60°

→ ∠AOC = 120°

→ ∠BAC = 90°

→ AO = OB = OC   [ ∴ Sides  ]

→ ∠OAB =  ∠OBA

→ OB = OA

→ In Δ  AOB,

→ Let the ∠ABO  = x = ∠ABC,

→ ∠ABO = ∠BAO

→ x + x + ∠AOB = 180 [ ∵ sum of angles in Δ ]

→ 2x = 180 - 60

→ x = 60  = ∠ABC