Question

O is the centre of the circle,∠AOB=90°,∠CBA=30°. find ∠BAC

Answer 1

angle subtended by the arc at the centre is double the angle subtended by it at any part of the circle
so angle AOB =90
therfore BCA =45
USING ANGLE SUM PROPERTY
IN TRIANGLE ABC
45+30+BAC=180
BAC =105 DEGREE
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