Question

O is the centre of the circle. BC is a diameter of the circle. OD I perpendicular to AB chord. If OD=4cm, BD=5cm, then CD=?
A)13 cm
B)√71 cm
C)√89 cm
D) None of these

Answer 1

Answer:

since it is given that who is the centre of the circle and BC is the diameter then join BD and CD.

in triangle BOD

by Pythagoras theorem it can be stated that BO will be 3

now since BO is the radius then BC will be 6 cm.

then then again by Pythagoras theorem we will get the answer

Answer 2

Answer:

√89cm

please mark it as brainliest

Step-by-step explanation:

by applying Pythagoras theorem in rt. triangle ODB

we get OB=√41 cm so BC=2√41 cm

then by applying Pythagoras theorem in rt. triangle ABC we get

AC=8cm

lastly by applying Pythagoras theorem in rt. triangle ADC we get

CD=√89cm