O is the centre of the circle chord A B 16 cm and radius of circle is 10 cm find the distance of the chord from the centre of the circle
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the distance of the chord from centre is 6 cm
Annu1345:
keshe aaya
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aloha!
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we are given AB= 16 { which is a chord }
and radius is given to be OB = 10 cm
now,
MB = 8 cm
OB = 10 cm
OM = ?
now by pythagoras theorem
OB² = OM² + MB²
OM² = OB² - MB²
OM² = 10² - 8²
OM² = 100 - 64
OM² = 36
OM = √36
OM = 6 cm.
⊱ ────── {⋅. ✯ .⋅} ────── ⊰
hope it helps :)
⊱ ────── {⋅. ✯ .⋅} ────── ⊰
we are given AB= 16 { which is a chord }
and radius is given to be OB = 10 cm
now,
MB = 8 cm
OB = 10 cm
OM = ?
now by pythagoras theorem
OB² = OM² + MB²
OM² = OB² - MB²
OM² = 10² - 8²
OM² = 100 - 64
OM² = 36
OM = √36
OM = 6 cm.
⊱ ────── {⋅. ✯ .⋅} ────── ⊰
hope it helps :)
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