O is the centre of the circle. Chord RS is parallel to diametre PQ. If angle PQR =25° calculate angle RTS
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Since O is the centre and OP =OR =radius of the circle
and ∠OPR= ∴∠ORP=
and ∠OPR+∠ORP+∠POR=
⇒++∠POR=
∴∠POR=
NEXT
OR=OR=Radius of the circle ∴ It becomes an isoscles triangle and ∠ROS= ∴∠ORS=∠OSR= (Since the sum of angles in a triangle is
Since Points P,O ,Q are collinear ∴∠SOQ=-(+)=
and OS=OQ =Radius of the circle ∴∠OSQ=∠OQS=
∴∠RSQ=+=
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