Question

O is the centre of the circle. Chord RS is parallel to diametre PQ. If angle PQR =25° calculate angle RTS​

Answer 1

Answer:

Since O is the centre and OP =OR =radius of the circle

and ∠OPR= ∴∠ORP=

and ∠OPR+∠ORP+∠POR=

⇒++∠POR=

∴∠POR=

NEXT

OR=OR=Radius of the circle ∴ It becomes an isoscles triangle and ∠ROS= ∴∠ORS=∠OSR= (Since the sum of angles in a triangle is

Since Points P,O ,Q are collinear ∴∠SOQ=-(+)=

and OS=OQ =Radius of the circle ∴∠OSQ=∠OQS=

∴∠RSQ=+=