Question

O is the centre of the circle. Find the length of radius, if the chord of length 16 cm is at a distance of 6 cm from the centre​

Answer 1

Answer:

suppose AB is the chord and OM perpendicular to AB

we know that distance from centre to the chord bisects the circle

so, AM=MB=8cm

OM=6cm

and OA is radius of circle

Now in Tri.AOM

OA^2=OM^2 + AM^2

OA^2=36 + 64

OA^2=100

OA = 10

so, radius of circle is 10 cm

HOPE THIS ANSWER WOULD HELP YOU.

Answer 2

Step-by-step explanation:

given : AB Is a chord of 16cm and the distance between OM = 6cm

we have to find the raidus

proof : In right angled triangle OMB

OM = 6CM, MB = 1/2 AB => 1/2*16 => 8cm

And OB = ?

so, by using Pythagoras therom

(OB)²= (OM)² + ( MB )²

(0B)² = (6)² + (8)²

(OB)²= 36 + 64

(OB)² =

OB = √

OB = 10

Therefore the length of raidus is 10cm