Question

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O is the centre of the circle having radius 5 cm. AB and AC are two chords such that AB=AC=6cm. If OA meets BC at P, then OP = ___


[step by step explanation plz
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Answer 1

Answer:

here's ur answer dude .....

Answer 2

Answer:

AB^2 = AP^2 + BP^2

6^2 = AP^2 + BP^2

36 = AP^2 + BP^2 eq 1

OB^2 = OP^2 + BP^2

5^2 = OP^2 + BP^2

25 = OP^2 + BP^2 eq2

eq1 -eq2

11 = AP^2 -OP^2

11 = (AP+OP)(AP-OP)

11 = OA(AP-OP)

11 = 5(AP-OP)

AP -OP = 11/5

AP + OP = 5

2OP = 5- 11/5

2OP = 14/5

OP = 7/5

OP= 1.4 cm