Question

O is the centre of the circle .If angle AOB=60 then find angle ACO

Answer 1

CO=AO (radii of the same circle)

Angle 1 + Angle AOB = 180 degree

( Linear Pair)

Angle 1 = 180 - Angle AOB

Angle 1 = 180- 60= 120 degree

Angle 1 + Angle 2+ Angle 3= 180 degree

( Angle Sum Property)

Angle 2= Angle 3

( angle opposite to equal sides)

Thus,

Angle 1 + 2 X ( Angle 2) = 180 degree

2 X ( Angle 2) = 180 - 120

Angle 2 =

$60 \div 2 = 30$

Angle 2= Angle 3 = 30 degree

Angle 2 is angle ACO

Therefore, Angle ACO= 30 degree.

Hope it helps

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