O is the centre of the circle. If <BOA = 90° and <COA = 110°,Find < BAC
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80°
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ANSWER
From the diagram.
∠BOA=90°
∠COA=110°
We know that in the center of the circle angle is 360°
∠COB=360°−90°+110°
=360°−200°
=160°
∠COB=2∠CAB
160°=2∠CAB
∠CAB=
2
160°
=80°
∴∠BAC=80
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