Question

O is the centre of the circle of radius 5 cm AB and CD are two parallel chords, on the

either side of the centre, AB = 6cm and CD = 8cm. Find the distance between the two

chords.​

Answer 1

Answer:

• the distance between two equal chords is nothing but the perpendicular to the chords from the centre.

Consider, ∆ AOB and ∆COD

AB||CD( given)

CO=OB(radii of same circle)

AO=OD(radii of same circle)

Hence. ∆ AOB is congurent to ∆COD

Answer 2

$\huge \color{maroon}ANSWER:$

Let the chord AB = 6 cms

chord CD = 8 cms

Let O be the centre of the circle.

Draw OM and ON perpendicular to AB & CD respectively.

Then,

AM = 3 cms and CN = 4 cms since the perpendicular from the centre to the chord bisects the chord.

Therefore we get OM = 4 cms and ON = 3 cms.

Hence the distance between the chords = MN = OM+ON = 4+3 = 7 cms.