O is the centre of the circle.prove that
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Step-by-step explanation:
∠EBF = 1/2∠EOF = 1/2∠z [∵ Angle subtended by an arc of a circle at the centre in twice the angle subtended by it at any point of the remaining part of the circle] [∵ Angle subtend by any arc of a circle at the centre is twice the angle subtended by it at any point of the remaining part of the circle] In quadrilateral ABCD ∠ABC + ∠BCD + ∠CDA + ∠BAD = 2 × 1800 [ Angle Sum Property of a quadrilateral] => 1800 - 1/2∠z + ∠y + 1800 - 1/2∠z + ∠x = 2 × 1800 => ∠x + ∠y = ∠zRead more on Sarthaks.com - https://www.sarthaks.com/76215/in-figure-o-is-the-centre-of-the-circle-prove-that-x-y-z
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