o is the centre of the circle the angle subtended by the arc BCD at the centre is 140 degree BC is produced by P find Angle B A D and angle DCP
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angle BAD=1/2(angle BOD) (angle at the center is twice the angle at the remaining circumference)
angle BAD=70
in triangle BOD,
OB=OD
<ODB=<OBD=180-140/2=20
<DBP=<DCP=20. (angle on same segment are equal )
angle BAD=70
in triangle BOD,
OB=OD
<ODB=<OBD=180-140/2=20
<DBP=<DCP=20. (angle on same segment are equal )
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