O is the centre of the circle whose radius is 41 CM. The length of the chord PQ of the circle is 80 cm. Find the distance of the chord from the centre O.
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PO^2 = OM^2 + PM^2 ( hypothenus)
PM Is half of PQ
PM = 80 / 2
PM = 40 cm
OM Is radius = 41 cm
PO^2 =(41 × 41) + (40 × 40)
PO^2 = 1681+1600
PO^2 = 3281cm^2
PO = √3281
PO = 57.28cm
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therefore distance of chord PQ from centre O is 9cm
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