Question

O is the centre of the circle with r 5 cm, ab||cd,ab=6 cm find op

Answer 1

Answer:

AP = 3 {radius when perpendicular to chord bisects it }

AP = 3 {radius when perpendicular to chord bisects it }QC = 4 {radius when perpendicular to chord bisects it }

AP = 3 {radius when perpendicular to chord bisects it }QC = 4 {radius when perpendicular to chord bisects it }Applying pythagoras theorem

AP = 3 {radius when perpendicular to chord bisects it }QC = 4 {radius when perpendicular to chord bisects it }Applying pythagoras theorem In OAP

AP = 3 {radius when perpendicular to chord bisects it }QC = 4 {radius when perpendicular to chord bisects it }Applying pythagoras theorem In OAPOP=4

AP = 3 {radius when perpendicular to chord bisects it }QC = 4 {radius when perpendicular to chord bisects it }Applying pythagoras theorem In OAPOP=4In OCQ

AP = 3 {radius when perpendicular to chord bisects it }QC = 4 {radius when perpendicular to chord bisects it }Applying pythagoras theorem In OAPOP=4In OCQOQ=3

AP = 3 {radius when perpendicular to chord bisects it }QC = 4 {radius when perpendicular to chord bisects it }Applying pythagoras theorem In OAPOP=4In OCQOQ=3 OP=PQ+OQ

AP = 3 {radius when perpendicular to chord bisects it }QC = 4 {radius when perpendicular to chord bisects it }Applying pythagoras theorem In OAPOP=4In OCQOQ=3 OP=PQ+OQ4=PQ+3

AP = 3 {radius when perpendicular to chord bisects it }QC = 4 {radius when perpendicular to chord bisects it }Applying pythagoras theorem In OAPOP=4In OCQOQ=3 OP=PQ+OQ4=PQ+3therefore PQ = 1