Question

O is the centre of the circle with radius 14 cm if angle P OR=90° then find:a) area∆POQ b) area of minor segment c) area of major segment PBQ​

Answer 1

Answer:

MATHS

In the given figure O is the centre of circle of radius 28 cm. Find the area of the minor segment ASB.

question

November 22, 2019avatar

Viswanadham Vadisetti

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ANSWER

Given radius=28cm, θ=45

∘

Area of minor segment = Area of sector OAB - Area of ΔOAB

Area of sector OAB =

360

πr

2

×θ=(

7

22

×

360

1

×(28)

2

×45)cm

2

=308cm

2

Area of ΔOAB=

2

1

×OA×OB×sin45

∘

[∵AreaofΔABC=

2

1

AB×AC×sinA]

=

2

1

×28×28×

2

1

cm

2

=14×14×

2

cm

2

=196×1.414cm

2

=277.144cm

2

∴ Area of minor segment =(308−277.144)cm

2

=30.856cm

2