o is the centre of tht circle and angle bod =150 /find anle bad and dcp
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Answer:
Step-by-step explanation:
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∠BAD = ∠DCP = 75°
Step-by-step explanation:
To find,
∠BAD = 1/2 of ∠BOD (∵ Angle detached by an arc on the center is double of its circumference).
∵ ∠BAD = 150/2
= 75°
∠BCD = 180 - 75° (180° is the sum of angles of a cyclic Quadrilateral)
= 105°
Thus,
∠DCP = 180° - 105° (Linear Pair)
= 75°
Learn more: Find the angle
brainly.in/question/14728918
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