Question

O is the circumcenter of the isosceles triangle ABC, whose AB= AC , the point A and O are opposite in side of angle BOC =100° , let us write by calculating the value of angle abc and angle abo

please tell me clearly .....​

Answer 1

Answer:

Step-by-step explanation:

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if AB = AC [ then angle ABC = angle ACB]

let angle ABC and angle ACB be x

since, the circumcentre acts as an angle bisector

angle ABO = angle  ACO = x/2

as ABO and ACO is half of ABC and ACB.....

so by angle-sum property,

ABO + ACO + BOC = 180°

2(x/2) + 100 = 180°

x = 180-100

(ABC)x = 80°

ABO = x/2 = 80°/2 = 40°

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