'O' is the circumcentre of ∆ABC; if ∠OAB = 35°, find ∠ACB
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Since O is the circumcenter, OA = OB + OC (being the radii of the circle).
Hence triangles AOC, AOB AND BOA are and angles OAC = OCA; OBA = OAB and OBC = OCB.
In triangle AOB, angles B and A are35 degrees each and angle O = 180–35–35 = 110.
Similarly, in triangle AOC, A and C are 25 degrees each and angle O = 130 degrees.
Angle BOC = 360 - 110- 130 = 120 degrees.
Angle OBC = OCB = (180 - 120)/2= 30 DEGREES.
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