Math, asked by aira1208, 11 hours ago

'O' is the circumcentre of ∆ABC; if ∠OAB = 35°, find ∠ACB​

Answers

Answered by mufiahmotors
1

Answer:

hi

Step-by-step explanation:

here is ur answer

Since O is the circumcenter, OA = OB + OC (being the radii of the circle).

Hence triangles AOC, AOB AND BOA are and angles OAC = OCA; OBA = OAB and OBC = OCB.

In triangle AOB, angles B and A are35 degrees each and angle O = 180–35–35 = 110.

Similarly, in triangle AOC, A and C are 25 degrees each and angle O = 130 degrees.

Angle BOC = 360 - 110- 130 = 120 degrees.

Angle OBC = OCB = (180 - 120)/2= 30 DEGREES.

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