Question

O is the circumcentre of triangle ABC AD is perpendicular to BC prove that angle BAO =angle CAD

Answer 1

Answer:

in triangle BOC and triangle COD

BO = CO (both are radius)

∠BDO=∠CDO =90°

BD is common in both triangle

so both triangle are similar

so ∠BOD=∠COD

as we know angle at the center is double of the angle of corcumferece

∠BOC=2∠BAC

⇒2∠BOD=2∠BAC (as we proved above)

⇒∠BOD=∠A

Step-by-step explanation:

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