o केंद्र असलेल्या वर्तुळात रेख op लंब जीवा AB असून AB = 48 सेमी, op = 7 सेमी आहे तर वर्तुळाची त्रिज्या काढा.
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Given : O केंद्र असलेल्या वर्तुळात रेख OP लंब जीवा AB असून AB = 48 सेमी, op = 7 सेमी
In a circle with center O, the perpendicular on chord AB is OP
AB = 48 cm, op = 7 cm
To find : the radius of the circle.
Solution:
AB is chord
OP ⊥ AB
Hence P is the mid point of AB
AP = BP = AB/2 = 48/2 = 24 cm
Using Pythagorean theorem
OA² = AP² + OP²
=> OA² = 24² + 7²
=> OA² = 576 + 49
=> OA² = 625
=> OA = 25
Hence वर्तुळाची त्रिज्या = 25 सेमी
radius of the circle is 25 cn
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