Question

o. On the basis of following given standard electrode
potentials, arrange the metals in increasing order of
reducing capacity :
K+/K=-2.93 V, Ag+ /Ag=0.80 V
Hg++ /Hg = 0.79 V
Mg2+ /Mg =-2.37 V, Cr3+ /Cr=-0.74 V​

Answer 1

Answer:

reduction potential directily proportional to negative value of reducing power.so more negative value of reducing power best is reduction potential.

order will be:

K>Mg>Cr>Hg>Ag

Explanation:

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Answer 2

Explanation:

Hg2+/Hg = 0.79 V Mg2+/Mg = – 2.37 V, Cr3+/Cr = – 0.74 V Arrange these metals in their increasing order of reducing power. Answer: Lower the reduction potential more the tendency to get oxidized and thus more will be reducing power. Hence increasing order of reducing power of metal is Ag < Hg < Cr < Mg < K.

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