Question

o piece of thin wire in the form of en equilater
triangle of side 8.8 dm is bent into a circle
with no loss in wire find the diameter of the
circle​

Answer 1

Step-by-step explanation:

Answer. Perimeter of triangle=perimeter of circle. P of∆=p of circle. Hence, the diameter of the wire is 8.4dm

Answer 2

Answer:

Perimeter of equilateral triangle =3×side

=3×8.8

=26.4

Perimeter of circle must be equal to perimeter of triangle if there is no lose in wire.

Therefore, perimeter of circle =26.4

2×Pi×R=26.4

R×2=26.4/3.14

R×2=8.4

D=R×2

D=8.4dm