o solutie de acid sulfuric contine 343md de H2SO4,dizolvat in 350L solutie.Se cere:
a) Concentratia molara a solutiei de hidroxid de potasiu.
b) Determinati pH-ul si pOH-ul solutiei.
c)Calculati volumul solutiei de hidroxid de sodiu 0,01 necesar neutralizarii solutiei.
se dau:
Mase atomice:H=1,0=16,S=32
Answers
Answered by
1
pH=13
pH=-lg [H₃O⁺] = -lg 10⁻¹³ = 13
Kw=[OH⁻]*[H₃O⁺] = 10⁻¹⁴ (mol/L)² => [OH⁻] = 10⁻¹⁴/10⁻¹³ = 10⁻¹ mol/L
sau pH + pOH = 14 => pOH = 14-13 = 1
[OH⁻] = 10⁻pOH = 10⁻¹ mol/L
pH=-lg [H₃O⁺] = -lg 10⁻¹³ = 13
Kw=[OH⁻]*[H₃O⁺] = 10⁻¹⁴ (mol/L)² => [OH⁻] = 10⁻¹⁴/10⁻¹³ = 10⁻¹ mol/L
sau pH + pOH = 14 => pOH = 14-13 = 1
[OH⁻] = 10⁻pOH = 10⁻¹ mol/L
Answered by
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Hii friends hope u like answer as it is effective please don't say it is cheated on as up one answer is same cause question answer is only this❤️
pH=13
pH=-lg [H₃O⁺] = -lg 10⁻¹³ = 13
Kw=[OH⁻]*[H₃O⁺] = 10⁻¹⁴ (mol/L)² => [OH⁻] = 10⁻¹⁴/10⁻¹³ = 10⁻¹ mol/L
sau pH + pOH = 14 => pOH = 14-13 = 1
[OH⁻] = 10⁻pOH = 10⁻¹ mol/L
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