Chemistry, asked by rebecareby, 1 year ago

o solutie de acid sulfuric contine 343md de H2SO4,dizolvat in 350L solutie.Se cere:
a) Concentratia molara a solutiei de hidroxid de potasiu.
b) Determinati pH-ul si pOH-ul solutiei.
c)Calculati volumul solutiei de hidroxid de sodiu 0,01 necesar neutralizarii solutiei.
se dau:
Mase atomice:H=1,0=16,S=32

Answers

Answered by Anonymous
1
pH=13

pH=-lg [H₃O⁺] = -lg 10⁻¹³ = 13

Kw=[OH⁻]*[H₃O⁺] = 10⁻¹⁴ (mol/L)² => [OH⁻] = 10⁻¹⁴/10⁻¹³ = 10⁻¹ mol/L

sau pH + pOH = 14 => pOH = 14-13 = 1

[OH⁻] = 10⁻pOH = 10⁻¹ mol/L
Answered by kritsainju
0

Hii friends hope u like answer as it is effective please don't say it is cheated on as up one answer is same cause question answer is only this❤️

pH=13

pH=-lg [H₃O⁺] = -lg 10⁻¹³ = 13

Kw=[OH⁻]*[H₃O⁺] = 10⁻¹⁴ (mol/L)² => [OH⁻] = 10⁻¹⁴/10⁻¹³ = 10⁻¹ mol/L

sau pH + pOH = 14 => pOH = 14-13 = 1

[OH⁻] = 10⁻pOH = 10⁻¹ mol/L

If u like the answer than please rate and thanks

Hope u will mark me in brilliant list

Thanks :)(:

Similar questions