Question

o solve the equation by elimination
(1) 2x+y=4
3x +2y = 6​

Answer 1

${\boxed{\underline{\tt{\orange{Required \: \: answer:-}}}}}$

★GIVEN:-

Two Equations:-

• 2x + y = 4

• 3x + 2y = 6

★SOLVED USING:-

• Elimination Method

★SOLUTION:-

$: \longrightarrow \displaystyle \rm{2x + y = 4 } \\ \\ : \longrightarrow \displaystyle \rm{y = 4 - 2x....(1.)}$

Now,

$: \longrightarrow \displaystyle \rm{3x + 2y = 6 } \\ \\ \sf{put \: the \: value \: of \: y \: from \: (1.) \: into \: this \: equation} \\ \\ : \longrightarrow \displaystyle \rm{3x + 2(4 - 2x) = 6} \\ \\ : \longrightarrow \displaystyle \rm{3x + 8 - 4x = 6 } \\ \\ : \longrightarrow \displaystyle \rm{8 - x = 6 } \\ \\ : \longrightarrow \displaystyle \rm{x = 8 - 6 } \\ \\ { \boxed{ \underline{ \huge{ \blue{x = 2}}}}} \\ \\ \sf{Now \: Put \: the \: value \: of \: x \: into \: (1.) } \\ \\ : \longrightarrow \displaystyle \rm{y = 4 - 2(2)} \\ \\ : \longrightarrow \displaystyle \rm{y = 4 - 4} \\ \\ { \boxed{ \underline{ \huge{ \blue{y = 0}}}}}$

So, x = 2 and y = 0

★VERIFY:-

Put the values of x and y in these equations:-

• 2x + y = 4

${\boxed{\underline{\displaystyle{\sf{\bf{\red{L.H.S}}}}}}}$

$\rm{ = 2(2) + 0} \\ \\ \rm{ = 4}$

${\boxed{\underline{\displaystyle{\sf{\bf{\red{R.H.S}}}}}}}$

• 3x + 2y = 6

${\boxed{\underline{ \displaystyle{\sf{\bf{\red{L.H.S}}}}}}}$

$\rm{ = 3(2) + 2(0)} \\ \\ \rm{ =6 }$

${\boxed{\underline{\displaystyle{\sf{\bf{\red{R.H.S}}}}}}}$

Hence, Solved and Verified :)

Answer 2

x = 2

y =0

HOPE IT HELPS✿✿✿✿✿