Question

o solve the following equation,
(x²+2x)(x²+2x-11)+24=0​

Answer 1

Step-by-step explanation:

(x2 + 2x) (x2 + 2x – 11) + 24 = 0

Substituting x2 + 2x = m we get,

m (m – 11) + 24 = 0

m2 – 11m + 24 = 0

m2 – 8m – 3m + 24 = 0

m (m – 8) – 3 (m – 8) = 0

(m – 8) (m – 3) = 0

m – 8 = 0 or m – 3 = 0

m = 8 or m = 3

Resubstituting m = x2 + 2x we get,

x2 + 2x = 8 or x2 + 2x = 3

x2 + 2x – 8 = 0 ....... (i) or x2 + 2x – 3 = 0 ......(ii)

From (i), x2 + 2x – 8 = 0

x2 + 4x – 2x – 8 = 0

x(x + 4) – 2 (x + 4) = 0

(x + 4) (x – 2) = 0

x + 4 = 0 or x – 2 = 0

x = – 4 or x = 2

From (ii), x2 + 2x – 3 = 0

x2 + 3x – x – 3 = 0

x (x + 3) – 1(x + 3) = 0

(x + 3) (x – 1) = 0

x + 3 = 0 or x – 1 = 0

x = – 3 or x = 1

x = – 4 or x = 2 or x = – 3 or x = 1.