o some of the three term alan A.Pt 3. If the product of the first term and third term exceeds the 2nd term by 29, then find the Ap
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ʜᴇy ᴍᴀᴛᴇ ʜᴇʀᴇ ɪꜱ yᴏᴜ ᴀɴꜱᴡᴇʀ
Step-by-step explanation:
Sum of the three terms = a - d + a + a + d = 3a
Sum of the three terms = a - d + a + a + d = 3a3a = 33
Sum of the three terms = a - d + a + a + d = 3a3a = 33a = 11
Sum of the three terms = a - d + a + a + d = 3a3a = 33a = 11Also, from the given information, we have:
Sum of the three terms = a - d + a + a + d = 3a3a = 33a = 11Also, from the given information, we have:(a - d)(a + d) = a + 29
Sum of the three terms = a - d + a + a + d = 3a3a = 33a = 11Also, from the given information, we have:(a - d)(a + d) = a + 29a2 - d2 = 11 + 29 = 40
Sum of the three terms = a - d + a + a + d = 3a3a = 33a = 11Also, from the given information, we have:(a - d)(a + d) = a + 29a2 - d2 = 11 + 29 = 40121 - d2 = 40
Sum of the three terms = a - d + a + a + d = 3a3a = 33a = 11Also, from the given information, we have:(a - d)(a + d) = a + 29a2 - d2 = 11 + 29 = 40121 - d2 = 40d2 = 81
Sum of the three terms = a - d + a + a + d = 3a3a = 33a = 11Also, from the given information, we have:(a - d)(a + d) = a + 29a2 - d2 = 11 + 29 = 40121 - d2 = 40d2 = 81d = 9
Sum of the three terms = a - d + a + a + d = 3a3a = 33a = 11Also, from the given information, we have:(a - d)(a + d) = a + 29a2 - d2 = 11 + 29 = 40121 - d2 = 40d2 = 81d = 9Thus, the AP is
Sum of the three terms = a - d + a + a + d = 3a3a = 33a = 11Also, from the given information, we have:(a - d)(a + d) = a + 29a2 - d2 = 11 + 29 = 40121 - d2 = 40d2 = 81d = 9Thus, the AP is2, 11, 20, … or 20, 11, 2, …
ᴩʟꜱ ᴍᴀʀᴋ ᴍᴇ.ᴀꜱ ʙʀᴀɪɴʟɪᴇꜱᴛ
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