Question

O
T
P
In the given figure, find ZPQR.
20 - X
X + 70°
S
A​

Answer 1

Answer:

please add to brilliant list

Answer 2

Answer:

SQR is a straight line

∴ ∠SQT + ∠TQP + ∠PQR = 180°

⇒ x + 70° + 20° – x + ∠PQR = 180°

⇒ 90″ + ∠PQR = 180°

⇒ ∠PQR = 180°- 90° = 90°

Hence ∠PQR = 90°