Question

o The Equation of the tangent
to the Curve y= 4 + sin²x
at x=0 is
(a) y=2
(b) y=4
(c) y=3
(d) y = 6​

Answer 1

Answer:

y=4

Step-by-step explanation:

First of all differentiate the eqⁿ

y=4+sin²x

dy/dx=0+2sinx•cos

dy/dx=sin2x

dy/dx(at x=0)=sin0=0

Now eqⁿ of tangent dy/dx=y1-y2/x1-x2

Therefore y1-y2=x1-x2

y=4

Answer 2

given,

y= 4 + sin²x

First of all differentiate the equation

y=4+sin²x

dy/dx=0+2sinx•cos

dy/dx=sin2x

dy/dx(at x=0)=sin0

=0

Now equation of tangent

dy/dx=y1-y2/x1-x2

Therefore

y1-y2=x1-x2

y=4