o. Three 2 12 resistors, .A, B and C, are connected as shows in Figure 12.7. Each of them dissipates energy and can withstand a maximum power of 18W without melting.
Find the maximum current that can flow through the
three resistors?
Answers
Answered by
2
Answer:
where,
V= voltage across a resistor
I = current through the resistor
R = value of resistance.
The power dissipated by the resistor is given by P=
R
V
2
=I
2
R
thus I
2
=
R
P
Each resistance dissipates energy = 18 Watts
The maximum current through B or C or A is given by I
2
=
2 ohms
18 Watts
So I=3 Amperes maximum
Since the resistances B and C are connected in parallel, the current that comes from the resistance A is divided equally between the resistance B and C.
so current through B = current through resistance C =
2
1
× current through A
Since, the current passing thru resistor A is max = 3 amperes, then the current through resistor B and resistor C is 1.5 Amperes
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