Question

o two resistances of 12 2 & 4 de are
connect in parallel to cell of EMF 6 volt of
internal resistance lot find current in circuit
terminal Potential difference​

Answer 1

Answer:

Equivalent internal resistance of parallel connection r

eq

=

r

1

+r

2

r

1

r

2

∴ r

eq

=

1+2

1×2

=

3

2

Ω

Equivalent emf of cells in parallel connection E

eq

=[

r

1

E

1

+

r

2

E

2

]r

eq

∴ E

eq

=[

1

2

+

2

4

]×

3

2

=

3

8

V

Potential difference across 10Ω resistor, E=

R+r

eq

R

E

eq

∴ E=

10+

3

2

10

×

3

8

=2.5V

Explanation:

hope you are satisfied with the answer is