Question

O
. UJU
7.
The diagonal and one side of the rectangular field are 289 mtrs, and 161 mtrs
respectively. Find the other side.
(a) 180 mtrs. (b) 220 mtrs. (c)230 mtrs. (d) 240 mtrs​

Answer 1

Answer:

(d) 240

Step-by-step explanation:

Hey mate hope it helps...

here we apply, pythagoras theorem in rectangle ABCD where

side AB = 161 and,

diagnal AC =289

${ac}^{2} = {bc}^{2} + {ab}^{2} \\ {bc}^{2} = {ac}^{2} - {ab}^{2} \\ bc = \sqrt{ {289}^{2} - {161}^{2} } \\ bc = \sqrt{83521 - 25921 } \\ bc = \sqrt{57600} = 240$

and therefore (d) option is correct....

If it helped you please mark it as brainliest

Answer 2

AnswEr :

$\frak{Given}\begin{cases} \textsf{ \: \: \: Diagonal of rectangular field} = \frak{289~m}&\\ \\ \textsf{ \: \: \: One side of rectangular field} = \frak{161~m}\end{cases}$

Need to find: The other side of the rectangular field.

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$\underline{ \bigstar\:\sf{ Using\; Pythagoras\: Theorem~ In~ \Delta ABC \; :}}$⠀⠀

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$:\implies\sf (AB)^2 + (BC)^2 = (AC)^2 \\\\\\:\implies\sf (BC)^2 = (AC)^2 - (AB)^2 \\\\\\:\implies\sf ( BC)^2 = (289)^2 - (161)^2 \\\\\\:\implies\sf (BC)^2 = 83521 - 25921 \\\\\\:\implies\sf (BC)^2 = 57600 \\\\\\:\implies\sf BC = \sqrt{57600} \\\\\\:\implies\underline{\purple{\boxed{\pmb{\frak{BC = 240\;m}}}}}\:\bigstar$

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$\therefore{\underline{\textsf{Hence,~the~other~side~of~field~is~\textbf{ Option d) 240 m}.}}}$

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