Question

O using Cramer's rule, find the solution of linear equation
2x+3y-5=0 & 4x-5y+1=0​

Answer 1

$\text{The given equations are}$

$2x+3y=5\;\text{and}$

$4x-5y=-1$

$\triangle=\left|\begin{array}{cc}2&3\\4&-5\end{array}\right|$

$\triangle=-10-12=-22$

$\triangle_x=\left|\begin{array}{cc}2&5\\4&-1\end{array}\right|$

$\triangle_x=-2-20=-22$

$\triangle_y=\left|\begin{array}{cc}5&3\\-1&-5\end{array}\right|$

$\triangle_y=-25+3=-22$

$\textbf{By Cramers rule}$

$x=\frac{\triangle_x}{\triangle}$

$x=\frac{-22}{-22}=1$

$y=\frac{\triangle_y}{\triangle}$

$y=\frac{-22}{-22}=1$

$\therefore\textbf{The solution is x=1 and y=1}$

Find more:

Find x,y,z using cramers rule, if x-y+z=4, 2x+y-3z=0 and x+y+z=2

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