Chemistry, asked by ANSHUL29991, 1 year ago

O2 is bubbled through a water at 293 kelvin assuming that o2 exotic partial pressure of 0.85 bar calculate the solubility of o2 in gram per litre the value of henry's law constant for co2 is 34 kilo bar

Answers

Answered by sahilarora199587
0

Explanation:

Henry's law can be put into mathematical terms (at constant temperature) as

p=kHcp=kHc

where p is the partial pressure of the solute in the gas above the solution, c is the concentration of the solute and kH is a constant with the dimensions of pressure divided by concentration. The constant, known as the Henry's law constant, depends on the solute, the solvent and the temperature.

Some values for kH for gases dissolved in water at 298 K include:

oxygen (O2) : 769.2 L·atm/molcarbon dioxide (CO2) : 29.41 L·atm/molhydrogen (H2) : 1282.1 L·atm/mol

There are other forms of Henry's Law, each of which defines the constant kH differently and requires different dimensional units. In particular, the "concentration" of the solute in solution may also be expressed as a mole fraction or as a molality

Similar questions