Question

O2,N2,CL2: arrange in the increasing order of number of covalent bonds

Answer 1

it's your answer.......

Cl2<O2<N2.....

as chlorine have ...1 covalent bond..
oxygen have ......2 covalent bonds..
nitrogen have.....3 covalent bonds...

Answer 2

Answer:

The increasing order of the number of covalent bonds is $N_{2} > O_{2} > Cl_{2}$

Explanation:

• When electrons are exchanged between atoms, covalent bonds form.
• π (pie) and σ (sigma) are the two types of covalent bonds.
• Sigma bonds are formed when two atomic orbitals overlap one another head-to-head, whereas pi bonds are formed when two atomic orbitals overlap one another laterally.
• The oxygen molecule, $O_{2}$ has one σ bond and one π bond.
• The nitrogen molecule $N_{2}$ has one σ bond and two π bonds.
• The chlorine molecule $Cl_{2}$ has only one σ bond.
• Therefore, the increasing order of the number of covalent bonds is $N_{2} > O_{2} > Cl_{2}$.

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