Question

OA=3cm
<AOB=120°
PA=?​​

Answer 1

∠OAP = ∠OBP = 90° ( ∵ ∵ angle between tangent and radius from that point to centre is 90°) ∠AOB = 120° ∠AOP = ∠BOP =60°(equally divides) In ∠OAP ∠OAP+∠AOP+∠OPA= 180° ⟹ ⟹ ∠OPA = 180° - 60° - 90° = 30°Read more on Sarthaks.com - https://www.sarthaks.com/175174/in-the-figure-pa-and-pb-are-tangents-to-a-circle-with-centre-o-if-aob-120-then-find-opa?show=175181#a175181

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