OA=4. OC=12. OD=6 FIND OB
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hey..
here In this figure we considered two triangles namely (OAB,ODC)
we observe that -
angleOAB=angleODC (right angle)
& angleAOB=angleODC
so the triangles OAB~tringleODC (A-A similarity rule)
according to thales theorem -
OA/OD=OB/OC=AB/D.C.
given that oa=4,OC=12,OD=6
THEN
4/6=OB/12
12×4=6OB
48=6OB
48/6=6OB
OB=8(answer)
I hope it is useful for you ..n.
thanks
please marks as brainlist
here In this figure we considered two triangles namely (OAB,ODC)
we observe that -
angleOAB=angleODC (right angle)
& angleAOB=angleODC
so the triangles OAB~tringleODC (A-A similarity rule)
according to thales theorem -
OA/OD=OB/OC=AB/D.C.
given that oa=4,OC=12,OD=6
THEN
4/6=OB/12
12×4=6OB
48=6OB
48/6=6OB
OB=8(answer)
I hope it is useful for you ..n.
thanks
please marks as brainlist
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