OA=OB and OD=OC. Show that 1.TriangleAOC is congruent to Triangle BOC. 2.AD II BC
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In△AOD&△BCO
=>OD=OC (given)
OA=OB(given)
∠AOD=∠COB (vertically opposite)
=>△AOD≅△BOC
∠OAD=∠OBC(angles corresponding to congruent sides)
[∵ AD & BC make equal angles with the same line AB]
HenceAD∣∣BC
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