OA,OB,OC,OD,OE and OF are six roads and all join at a point 'O'. These roads make angles (∠A ∠B and ∠C ∠ D and ∠E ) according to the figure. Roads OD and OE are perpendicular to each other AD & CF are straight lines and intersect each other at 'O' if ∠A:∠B:∠C are in the ratio 2:3:4. A teacher showed this figure to all the students of maths and asked the following
Answers
1. What is the angle between OB and OC roads ?
Road OB and road OC makes the ∠b
We are given,
∠A: ∠B : ∠C are in the ratio of 2:3:4 respectively.
∴Let , their common multiple be 'x'
- ( Angles forming linear pair )
Measure of ∠b = 3x
= 3 (20)
= 60°
Option ( C ) is Correct .
2. What is the value of ∠d ?
We are given,
AD and CF are straight lines.
which means,
- ( Vertically opposite angles )
∠COD = 4x
= 4 (20)
= 80°
Option ( D ) is Correct .
3. What is the complementary angles out of the four option ?
We know that,
Complementary angles are the pair of angle with the sum of 90 ° .
We are given ,
AD and CF are straight lines and OE is perpendicular
Conclusion - There's only one complementary angle in the figure
Option ( D ) is Correct.
Answers are:
a) (option c) 60 degrees
b) (option b) 40 degrees
c) (option d) ∠D and ∠E
Step-by-step explanation:
a) Since ∠A:∠B:∠C is in the ratio 2:3:4, let them be 2x, 3x, and 4x.
Thus, the sum of these angles is 180 degrees (angles form a straight line)
Thus, ∠A = 2x = 40, ∠B = 3x = 60, and ∠C = 4x = 80
- So, the angle between OB and OC is b = 60 degrees. (option c)
b) ∠ D = ∠ A ( vertically opposite angle)
- So, ∠ D = 40 degrees(option b)
c) Complementary angles add up to give the sum 90 degrees.
- From the figure, the sum of ∠D and ∠E will give 90 degrees. (option d)